law md5_hash_split3

bend-osdev-crypto@0.1.0.0 · LAWS.bend:1282

import Base
import bend-osdev-bytes@0.1.0.0/bytes.bend as B
import bend-osdev-hashes@0.1.0.0/md5.bend as HM5

1282# MD5 (hashes): and for every split into three
1283law md5_hash_split3:
1284  for +a: B.Octets
1285  for +b: B.Octets
1286  for +c: B.Octets
1287  {HM5.HsMd5.final(HM5.HsMd5.update(HM5.HsMd5.update(HM5.HsMd5.update(HM5.HsMd5.init(), a), b), c)) == HM5.HsMd5.digest(B.Octets.append(a, B.Octets.append(b, c))) : B.Octets}