def cnt.d2
import bend-osdev-acpi@0.1.1.0/PROOF.bend as PROOFimport Base
import bend-osdev-bytes@0.1.1.0/bytes.bend as B
1952def cnt.d2(+k: Nat, +lt: {Nat.is_lt(Nat.add(2n, k), 256n) == True{} : Bool}) -> {U32.to_nat(B.byte(U32.from_nat(Nat.add(2n, k)))) == Nat.add(2n, k) : Nat}:
1953 match k:
1954 case 0n:
1955 {==}
1956 case 1n+p:
1957 cnt.d3(p, lt)